CSIR NET JRF MATHEMATICS VIDEO LECTURES.In This videos i solved part a questions of CSIR NET MATHEMATICS. Watch and Subscribe the channel if you like them
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VIDEO LECTURE ON PERMUTATIONS AND COMBINATIONS- BASIC PRINCIPLE OF COUNTING
VIDEO LECTURE ON PERMUTATIONS AND COMBINATIONS- BASIC PRINCIPLE OF COUNTING
https://www.youtube.com/watch?v=tmcLbCcXT_w
In the video I explained about permutations and combinations-a basic principle of counting.Usually permutations and combinations comes under combinatorial analysis which is highly used in solving problems of probability theory.The basic principle of counting is simple and everyone must know it before going to probability.This video is useful for competitive exam preparation like IIT JAM,CSIR...
CSIR NET MATHEMATICS JUNE 2015 QUESTION PAPER
CSIR NET MATHEMATICS JUNE 2015 QUESTION PAPER
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download the csir net mathematics december 2014 question paper
CSIR NET MATHEMATICS DECEMBER 2014 QUESTION PAPER is now available at http://mathexamtips.blogspot.in .Soon we are going to provide the clear solutions of CSIR NET MATHEMATICS DECEMBER 2014 QUESTION PAPER
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download the csir net mathematics june 2014 question paper
CSIR NET MATHEMATICS JUNE 2014 QUESTION PAPER is now available at http://mathexamtips.blogspot.in .Soon we are going to provide the clear solutions of CSIR NET MATHEMATICS JUNE 2014 QUESTION PAPER
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100 SOLVED QUESTIONS FOR CSIR,GATE, SET AND OTHER COMPETITIVE EXAMS-PART 3
100 SOLVED QUESTIONS FOR CSIR,GATE, SET AND OTHER COMPETITIVE EXAMS-PART 3
Question 10: Let H=\{e,(12)(34)\} and K=\{e,(12)(34),(13)(24),(14)(23)\} be subgroup of S_4, where e denotes the identify element of S_4. Then
H and K are normal subgroup of S_4
H is normal in K and K are normal in A_4
H is normal in A_4 but not in S_4
H is normal in S_4 but H is n...
100 SOLVED QUESTIONS FOR CSIR,GATE, SET AND OTHER COMPETITIVE EXAMS-PART2
100 SOLVED QUESTIONS FOR CSIR,GATE, SET AND OTHER COMPETITIVE EXAMS-PART 2
Question 6: The number of elements in the set \{m:1\leq m \leq 1000, m \text{ and } 1000 \text{ are relatively prime} \} is
1.~100 \quad 2.~250 \quad 3.~300 \quad 4.~400
Answer: The question asks for \phi(1000).
And \phi(n) can be calculated using following formula.
1. \phi(p_1^{m_1}p_2^{m_2} \cdots p_r^{m_r}) = \phi(p_1^{m_1})\phi(p_2^{m_2}) \cdots \phi(p_r^{m_r}).
2. \phi(p^m) = \begin{cases}2^{m-1} &\text{ if } p= 2 \\ p^m - p^{m-1} &\text{...